I have $\bar{x}_i$ for $ 1\leq i\leq m$ as the estimated mean of each of $m$ samples with size $n$ of a random variable $X$. I want to estimate the value of $\sigma_\bar{X}$ with this information. I guess that the correct estimate is:
$$\hat\sigma_\bar{X}=\sqrt{\frac{\sum_{i=1}^m(\bar{x_i}-\bar{\bar{x}_i})^2}{m-1}}.$$
I would like to know if it's correct and if not the method for find the correct estimation.
( I haven't access to the $mn$ original values)
There is no such thing as a correct estimator, although sometimes there are optimal ones according to certain criteria.
Preaching aside, you can just think of your successive measurements of the sample mean as samples of the random variable $\bar X_n.$ The estimator you wrote down is a very popular estimator of the standard deviation for $m$ samples of a random variable, so it's probably not a bad choice, given that the fairly weak assumptions that make this estimator typically have good properties hold.
If the individual random variables comprising the groups of size $n$ are known to be independent and you have all the data (not just the sample means) you could also just do the sample variance of the whole batch and use the fact that $Var(\bar X) = Var(X)/n.$