I am trying to evaluate the following limit: $$\lim\limits_{x \rightarrow \infty}x2^{x}=\lim\limits_{x \rightarrow \infty}xe^{x\ln{2}}=\lim\limits_{x \rightarrow \infty}\frac{x\ln{2}e^{x\ln{2}}}{\ln{2}}$$
I hope you can help me. Thank you
2026-04-08 21:28:11.1775683691
How to evaluate $\lim\limits_{x \rightarrow \infty}x2^{x}$ without using L'Hospital's rule?
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