I want to evaluate the integral as y tends to zero. That is, $\int_0^y\sqrt{\log(1+1/x)}dx$ as $y$ tens to zero.
2026-04-11 23:46:51.1775951211
How to evaluate the integral , $\int_0^y\sqrt{\log(1+1/x)}dx$ as $y$ tens to zero.?
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Hint:
$$\sqrt{\log(1 + 1/x)} \leqslant \frac{1}{\sqrt{x}}$$