How to express the basis $\beta = \{1, (x-1), (x-1)^2, (x-1)^3\}$ in matrix form

64 Views Asked by At

For a change of basis question, I have the following bases:

$$\epsilon = {1, x^1, x^2, x^3}$$ and $$\beta = {1, (x-1), (x-1)^2, (x-1)^3}$$

I believe that $\epsilon$ can be expressed as $$ \begin{bmatrix} 1&0&0&0\\ 0&1&0&0\\ 0&0&1&0\\ 0&0&0&1 \end{bmatrix} $$

However, I am unsure on how to proceed with turning $\beta$ into a matrix. I have an attempt that translates to $$ \begin{bmatrix} 1&0&0&0\\ 0&(x-1)&0&0\\ 0&0&(x-1)&0\\ 0&0&0&(x-1) \end{bmatrix} $$ but I highly doubt that is correct.

Edit: I have checked this question here: How do I express ordered bases for polynomials as a matrices? Linear Algebra.

but it lead me nowhere for my specific qualm.

1

There are 1 best solutions below

0
On BEST ANSWER

You expand the expressions and check the coefficients and put them in the right place in the matrix.

First column: $$(1)\cdot 1$$ Second column: $$1\cdot x + (-1)\cdot 1$$ Third column: $$(x-1)^2 = 1\cdot x^2 + (-2)\cdot x + 1\cdot 1$$ Fourth column: $$(x-1)^3 = 1\cdot x^3 + (-3)\cdot x^2 + 3\cdot x + (-1) \cdot 1$$

$$\begin{bmatrix}1&-1&1&-1\\0&1&-2&3\\0&0&1&-3\\0&0&0&1\end{bmatrix}$$