How to find asymptotic behaviour?

313 Views Asked by At

How do we find asymptotic behavior of Hermite polynomials? I tried to check, but i can only find the final expression but not the method.

1

There are 1 best solutions below

1
On

You can prove by induction that the $n$th derivative of $e^{-x^2/2}$ is $e^{-x^2/2}$ multiplied by a polynomial of degree of $n$ with leading factor $(-1)^n$, hence the (probabalist's) Hermite polynomials all have leading factor $1$, and so tend to positive infinity asymptotically.