The equation is $4^p-2^p-1=0$
How to get $2^p = (1+\sqrt{5})/2$ from that equation?
Please help.
it is $(2^p)^2-2^p-1=0$ with $t=2^p$ we get $$t^2-t-1=0$$ Can you solve this?
Copyright © 2021 JogjaFile Inc.
it is $(2^p)^2-2^p-1=0$ with $t=2^p$ we get $$t^2-t-1=0$$ Can you solve this?