How to get a compact subset where some conditions hold uniformly?

31 Views Asked by At

I'm reading Mattila's book "Geometry of sets and measures in Euclidean spaces". At the p. 222 in proof of Theorem 16.2 we have the following proposition:

Let $\varepsilon >0$. Since E ($\mathcal H^m(E) < \infty$) has positive lower density ($\Theta^m_*(E, \cdot) > 0$) $\mathcal H^m$ a.e. on $E$, there are a compact subset $F$ of $E$ with $\mathcal H^m(E \setminus F) < \varepsilon$ and positive numbers $\delta$ and $r_0$ such that \begin{equation}\label{} \mathcal H^m \big( E \cap B(a,r)\big) > \delta r^m \tag{$\star$} \end{equation} for $a \in F$, $0 < r < r_0$.

I know that for a.e. point $a \in E$ there exists a $r_0=r_0(a)$ and $\delta=\delta(a)$ such that condition $(\star)$ holds. Also, Borel regular measures (like a $\mathcal H^m$ in $\mathbb R^n$) can be approximated in the next way: if $\mathcal H^m(A) < \infty$ and $\varepsilon >0$ there a closed set $C$ s.t. $\mathcal H^m(A \setminus C) < \varepsilon$.

I can't understand how to find such set $F$.

1

There are 1 best solutions below

0
On

I found an answer to my question. Here we will use following properties of $\Theta^m_*$:

  1. $\Theta^m_*$ is a Borel function,

  2. $\Theta^m_*(E, x) = \lim\limits_{\delta\to 0} \inf\limits_{r < \delta} r^{-m} \mathcal H^m\big(E \cap B(x,r)\big)$ and $\inf\limits_{r < \delta} r^{-m} \mathcal H^m\big(E \cap B(x,r)\big)$ is Borel function too.

Since $\mathcal H^m(E)<\infty$ we can find $\mathcal H^m$-measurable set $B\subset E$ with $\mathcal H^m(E\setminus B) < \varepsilon$ and $$ \inf\limits_{r < 2^{-k}} r^{-m} \mathcal H^m\big(E \cap B(x,r)\big)\rightrightarrows \Theta^m_*(E, x) \quad\text{for $x\in B$} \tag{1}. $$ It's Egorov's theorem.

Again $\mathcal H^m(B) < \infty$ and $\Theta^m_*$ is a measurable function. By Lusin's theorem we obtain that there exists a compact set $F$ such that $\mathcal H^m(B\setminus F) < \varepsilon$ and $\left. \Theta^m_*(E, \cdot)\right|_F$ is a continuous function and $\Theta^m_*(E,x) \ge \eta$ for some $\eta >0$ and for all $x\in F$. That's why we can find a $r_0$ such that $$ \inf\limits_{r < r_0} r^{-m} \mathcal H^m\big(E \cap B(x,r)\big) > \Theta^m_*(E,x) - \eta/2\ge \eta/2 \quad\text{ for all $x\in F$}. $$