If by "angle of the vector" you mean the angle between the vector and the positive side of the $\;x$-axis and counterclockwise, which is the usual agreement, then
$$x=3\cos40^\circ\;,\;\;y=3\sin40^\circ\;,\;\;\text{and the vector is then}\;\;\binom xy$$
4
Bumbble Comm
On
In polar coordinates, you already do!
Otherwise draw a picture with horizontal leg of length $x$ and vertical leg of length $y$, take the sine and cosine of the angle and solve for $x$ and $y$.
If by "angle of the vector" you mean the angle between the vector and the positive side of the $\;x$-axis and counterclockwise, which is the usual agreement, then
$$x=3\cos40^\circ\;,\;\;y=3\sin40^\circ\;,\;\;\text{and the vector is then}\;\;\binom xy$$