It looks fairly simple:
$$\int \frac{dx}{\sqrt{2x-5}}$$
The answer is $$\sqrt{2x-5}$$
How is this done?
Make the substitution $$u = 2x-5$$. Then $$du = 2 dx $$.
So after the change of variables, we have $$\frac{1}{2}\int \frac{1}{\sqrt {u}} du$$
You should be able to take it from here.
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Make the substitution $$u = 2x-5$$. Then $$du = 2 dx $$.
So after the change of variables, we have $$\frac{1}{2}\int \frac{1}{\sqrt {u}} du$$
You should be able to take it from here.