How to isolate the variable $v$ buried deep in a relativity formula?

Question

Finding $v$ in $v = L[1-(v^2/c^2)]/t$

Closest attempt: $[1-(c^2/v^2)]v = L/t$

I've been working on this since yesterday. I think I need some help.

Answer 1

\begin{equation} v = L(1-v^2/c^2)/t \hspace{10mm}\Rightarrow \hspace{10mm} (t/L)v = 1 - (1/c^2)v^2 \hspace{10mm}\Rightarrow \hspace{10mm} (1/c^2)v^2 + (t/L)v - 1 = 0. \end{equation}

Now use the abc formula.