What would be the force F to keep the rod AB in equilibrium?
I got confused while using Lami's theorem.
$$\frac{F}{\sin160^\circ}=\frac{F_1}{\sin60^\circ}=\frac{W}{\sin140^\circ}$$
If F is keeping it in equilibrium, I can also write, $F^2=W^2+F_1^2+2WF_1\cos160^\circ$
Please give me the hint where am I doing wrong? Have I done any mistake in angle calculation? Thanks in advance.