How to Prove $(-1)^{\frac{1}{2}}$ = i?

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What would be a formal way to prove the above statement?

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$$\begin{align} (-1)^{1/2} &=e^{\ln{(-1)}/2}\\ &=e^{i\pi/2}\\ &=\cos{(\pi/2)}+i\sin{(\pi/2)}\\ &=i\\ \end{align}$$ Assuming the principal valued complex natural logarithm.