I know $\det(AB)=\det(A)\det(B)$. How can i prove using group theory if $A,B$ square matrices and I know $A, B\in GL(n,R)$. If the matrices were not square, it would be correct to say that it is valid?
2026-04-05 22:07:53.1775426873
How to prove $\det(AB)=\det(A)\det(B)$ using group theory? $A,B\in GL(n,R)$
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2
Note that $$ det(AB)=det(A)det(B)$$ makes sense only for square matrices.
As you know, $det(M)$ is defined only when M is a square matrix M.