My question concerns on the one hand a specific inequality and on the other hand a general strategy on how to approach inequalities in general.
Usually I don't have problems using induction in order to prove equalities. But wih inequalities my brain just stops working.
Given $n^2-2n-1>0$ for $n>3$.
I would like to prove that via induction from $n-1$ to $n$.
So $(n-1)^2-2(n-1)-1=n^2-2n+1-2n+2-1=n^2-4n+2$.
From here on I just don't have a clue...
First you prove the base case: clearly for $n=4$ you have $4^2-2\cdot 4-1>0$.
So you assume it holds for $n-1$ (where $n>4$) and then prove it holds for $n$.
So you're assuming that $n^2-4n+2>0$.
You want to prove that then $n^2-2n-1>0$.
Well, this is clear, since $n^2-2n-1>n^2-4n+2,\forall n>4$.
However, induction here proves $n^2-2n-1>0,\forall n>3$ with $n$ integer. This doesn't prove that it holds for all real numbers in $(3;+\infty)$.
Alternatively, $n^2-2n-1=(n-1)^2-2$. Here we even more clearly have that if $(n-1)^2-2>0,n>3$, then $n^2-2>(n-1)^2-2>0$.