The language $\{a,b,c\}^*\setminus L$ is the language of squarefree words over $\{a,b,c\}$. The link gives two examples of infinite squarefree words over $3$-element alphabets. The obvious idea is to take a long enough squarefree word $w$ and apply the pumping lemma to $ww$, but I don’t see any obvious way to ensure that the shortened word is squarefree. (Clearly the only useful pumping is down.)
Added: I really don’t see how to use the pumping lemma directly. However, the class of regular languages is closed under complementation, and given the existence of arbitrarily long squarefree words over $\{a,b,c\}$, it’s easy to use the pumping lemma to show that the language of squarefree words over $\{a,b,c\}$ is not regular.
Completely revised, and not an answer.
The language $\{a,b,c\}^*\setminus L$ is the language of squarefree words over $\{a,b,c\}$. The link gives two examples of infinite squarefree words over $3$-element alphabets. The obvious idea is to take a long enough squarefree word $w$ and apply the pumping lemma to $ww$, but I don’t see any obvious way to ensure that the shortened word is squarefree. (Clearly the only useful pumping is down.)
Added: I really don’t see how to use the pumping lemma directly. However, the class of regular languages is closed under complementation, and given the existence of arbitrarily long squarefree words over $\{a,b,c\}$, it’s easy to use the pumping lemma to show that the language of squarefree words over $\{a,b,c\}$ is not regular.