$\lvert J_0^{''}(x)\rvert < \dfrac {1} {2}$
How do I prove the above inequation?
From the above graphic it is clear that $\lvert J_0^{''}(0)\rvert=0.5$ is the maximum that the function can have. But how do I prove it?
$\lvert J_0^{''}(x)\rvert < \dfrac {1} {2}$
How do I prove the above inequation?
From the above graphic it is clear that $\lvert J_0^{''}(0)\rvert=0.5$ is the maximum that the function can have. But how do I prove it?
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