How to prove the statement

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For all integers $a, b, c$, if $a | c$ and $b | c$, then $ab | c^2$.

How can I prove the statement is wrong or true?

My work so far: $a | c \land b | c \implies ab | c^2$ where $a,b,c \in \mathbb{Z}$.

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$$ a|c \implies c=k_1 a$$

$$b|c \implies c=k_2 b$$

$$ a|c \text { & } b|c \implies $$

$$ c^2= k_1k_2 ab \implies $$

$$ab|c^2$$