I saw the following problem
$$\left( x^{2x^{-\frac{1}{5}}} \right)^{-1}=\frac{1}{25}$$
and I was curious whether I should read it as
$$\left( (x^{2x})^{(-\frac{1}{5})} \right)^{-1}$$
or $$\left( x^{(2x^{\frac{1}{5}})} \right)^{-1}$$
to clarify, am I to raise 2x to the -1/5 power first, or raise $x^{2x}$ to the -1/5 power?
The first thing I would do is take the reciprocal of both sides: $x^{2x^{-1/5}}= 25$. From there, because you have "$x$" both as the base and in the exponent I expect you will need the "W function".