How to show that for a real symmetric matrix $A,~A$ can be written as $A=B-C$ where $B,C$ are positive definite real symmetric matrices?
Please help me ! I'm clueless.
2026-04-01 21:29:56.1775078996
How to show that $A=B-C$
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Let $C=cI$ where $I$ is the identity matrix and $c\gt0$ is chosen so that for each eigenvalue $\lambda$ of $A$, $c+\lambda\gt0$.