Given the set $A = \{f:\mathbb{Z} \rightarrow \{ 0,1 \} |$ if $n \geq m$ then $f(n) \geq f(m) \}$
How would I go about showing $A$ is countable?
Thank you!
Given the set $A = \{f:\mathbb{Z} \rightarrow \{ 0,1 \} |$ if $n \geq m$ then $f(n) \geq f(m) \}$
How would I go about showing $A$ is countable?
Thank you!
Hint If $f$ is not constant, show that there exists a smallest $k$ such that $f(k)=1$. Here smallest means $\forall m< k$ we have $f(m)\neq 1$.
What can you say about $f$ then?