I'm trying to solve an overdetermined system of five equations and four variables, but I'm not being successful in this task. I have the following unknowns, $F,G,K$ and $L$, and I need to solve $F$ and $L$ in terms of $G$ and $K$, that is
$$ F(G,K) \,\, ,\\ L(G,K) \,\, . $$
The system that I'm treating is the following:
$$ F + G = H + J \,\, ,\\ i F \omega -i G \omega =i H \sqrt{\omega ^2-V_0}-i J \sqrt{\omega ^2-V_0} \,\, , \\ H e^{i a \sqrt{\omega ^2-V_0}}+J e^{-i a \sqrt{\omega ^2-V_0}}=K e^{i a \omega }+L e^{-i a \omega } \,\, , \\ i H \sqrt{\omega ^2-V_0} e^{i a \sqrt{\omega ^2-V_0}}-i J \sqrt{\omega ^2-V_0} e^{-i a \sqrt{\omega ^2-V_0}}=i K \omega e^{i a \omega }-i L \omega e^{-i a \omega } \,\, , \\ K e^{i b \omega }+L e^{-i b \omega }=0 \,\, , \\ $$ where the constants $a,b \in \mathbb{R}$. How could I Solve this system?
Thanks in advance!
For each equation list the variables with the ones you want to keep left of a separator (|) and the unwanted variables or constants on the right.
1.(F,G|H,J)
2.(F,G|H,J)
3.(K,L|H,J)
4.(K,L|H,J)
5.(K,L|)
You want (F,G,K|) and (L,G,K|)
Note equation 5 is already in the form (L,K|) or as a function L(K).
To find (F,G,K|) you need equations 1 and/or 2 to get F but with H and J eliminated.
To isolate H and J combine equation 5 with 3 and 4 respectively to get rid of L.
Note equations 3 and 4 are linearly independant in H and J, the +/- sign difference.
5+3 -> 6.(K|H,J) , new equation 6
5+4 -> 7.(K|H,J) , new equation 7
Equations 6 and 7 are 2 linearly independent equations with respect to 2 unknowns H and J so H and J can be isolated.
6+7 -> 8.(K|H) and 9.(K|J) the two new equations 8 and 9.
Substitute 8 and 9 into 1 (or 2) to replace H and J by K to get (F,G,K|).
Running these instructions in maxima
Gives the results with equations all equal to zero.
$$-J-H+G+F$$
$$\sqrt{w^2-{\it Vo}}\,J-\sqrt{w^2-{\it Vo}}\,H-w\,G+w\,F$$
$$-e^ {- a\,i\,w }\,L-e^{a\,i\,w}\,K+e^ {- a\,i\,\sqrt{w^2-{\it Vo}}}\,J+e^{a\,i\,\sqrt{w^2-{\it Vo}}}\,H$$
$$w\,e^ {- a\,i\,w }\,L-w\,e^{a\,i\,w}\,K-\sqrt{w^2-{\it Vo}}\,e^ {- a\,i\,\sqrt{w^2-{\it Vo}} }\,J+\sqrt{w^2-{\it Vo}}\,e^{a\,i\,\sqrt{w ^2-{\it Vo}}}\,H$$
$$e^ {- b\,i\,w }\,L+e^{b\,i\,w}\,K$$
Answer for L(K):
$$\left[ L=-e^{2\,b\,i\,w}\,K \right] $$
$$e^{2\,b\,i\,w-a\,i\,w}\,K-e^{a\,i\,w}\,K+e^ {- a\,i\,\sqrt{w^2- {\it Vo}} }\,J+e^{a\,i\,\sqrt{w^2-{\it Vo}}}\,H$$
$$-w\,e^{2\,b\,i\,w-a\,i\,w}\,K-w\,e^{a\,i\,w}\,K-\sqrt{w^2-{\it Vo}} \,e^ {- a\,i\,\sqrt{w^2-{\it Vo}} }\,J+\sqrt{w^2-{\it Vo}}\,e^{a\,i \,\sqrt{w^2-{\it Vo}}}\,H$$
$$H=-{{\left(\left(\sqrt{w^2-{\it Vo}}-w\right)\,e^{2\,b\,i\,w}+ \left(-\sqrt{w^2-{\it Vo}}-w\right)\,e^{2\,a\,i\,w}\right)\,e^{-a\,i \,\sqrt{w^2-{\it Vo}}-a\,i\,w}\,K}\over{2\,\sqrt{w^2-{\it Vo}}}}$$
$$J=-{{e^ {- a\,i\,w }\,\left(\left(\sqrt{w^2-{\it Vo}}+w\right)\,e^{ 2\,b\,i\,w}+\left(w-\sqrt{w^2-{\it Vo}}\right)\,e^{2\,a\,i\,w} \right)\,e^{a\,i\,\sqrt{w^2-{\it Vo}}}\,K}\over{2\,\sqrt{w^2- {\it Vo}}}}$$
Answer for F(G,K):
$${{\left(\left(\sqrt{w^2-{\it Vo}}+w\right)\,e^{2\,b\,i\,w}+\left(w- \sqrt{w^2-{\it Vo}}\right)\,e^{2\,a\,i\,w}\right)\,e^{a\,i\,\sqrt{w^ 2-{\it Vo}}-a\,i\,w}\,K}\over{2\,\sqrt{w^2-{\it Vo}}}}+{{\left( \left(\sqrt{w^2-{\it Vo}}-w\right)\,e^{2\,b\,i\,w}+\left(-\sqrt{w^2- {\it Vo}}-w\right)\,e^{2\,a\,i\,w}\right)\,e^{-a\,i\,\sqrt{w^2- {\it Vo}}-a\,i\,w}\,K}\over{2\,\sqrt{w^2-{\it Vo}}}}+G+F$$
The extra equation 2, can be used to eliminate G and create a function F(K).
maxima code:
$$-{{\left(\left(\sqrt{w^2-{\it Vo}}+w\right)\,e^{2\,b\,i\,w}+\left(w -\sqrt{w^2-{\it Vo}}\right)\,e^{2\,a\,i\,w}\right)\,e^{a\,i\,\sqrt{w ^2-{\it Vo}}-a\,i\,w}\,K}\over{2}}+{{\left(\left(\sqrt{w^2-{\it Vo}} -w\right)\,e^{2\,b\,i\,w}+\left(-\sqrt{w^2-{\it Vo}}-w\right)\,e^{2 \,a\,i\,w}\right)\,e^{-a\,i\,\sqrt{w^2-{\it Vo}}-a\,i\,w}\,K}\over{2 }}-w\,G+w\,F$$
$$G=-{{\left(\left(\left(2\,w\,\sqrt{w^2-{\it Vo}}+2\,w ^2-{\it Vo}\right)\,e^{2\,b\,i\,w}+{\it Vo}\,e^{2\,a\,i\,w}\right)\, e^{2\,a\,i\,\sqrt{w^2-{\it Vo}}}+\left(2\,w\,\sqrt{w^2-{\it Vo}}-2\, w^2+{\it Vo}\right)\,e^{2\,b\,i\,w}-{\it Vo}\,e^{2\,a\,i\,w}\right) \,e^{-a\,i\,\sqrt{w^2-{\it Vo}}-a\,i\,w}\,K}\over{4\,w\,\sqrt{w^2- {\it Vo}}}}$$
$$F=-{{\left(\left({\it Vo}\,e^{2\,b\,i\,w}+\left(-2\,w \,\sqrt{w^2-{\it Vo}}+2\,w^2-{\it Vo}\right)\,e^{2\,a\,i\,w}\right) \,e^{2\,a\,i\,\sqrt{w^2-{\it Vo}}}-{\it Vo}\,e^{2\,b\,i\,w}+\left(-2 \,w\,\sqrt{w^2-{\it Vo}}-2\,w^2+{\it Vo}\right)\,e^{2\,a\,i\,w} \right)\,e^{-a\,i\,\sqrt{w^2-{\it Vo}}-a\,i\,w}\,K}\over{4\,w\, \sqrt{w^2-{\it Vo}}}}$$
Make the computer do the work.
To get L(G,K):
Solve 3.(K,L|H,J) + 4.(K,L|H,J) to isolate H and J to get equations:
10.(K,L|H) and 11.(K,L|J)
Then combine 1.(F,G|H,J) + 2.(F,G|H,J) to remove F.
12.(G|H,J)
Then substitute H and J from 10 and 11 into 12 to get 13.(G,K,L|)
The maxima instructions:
$$H={{e^{-a\,i\,\sqrt{w^2-{\it Vo}}-a\,i\,w}\,\left(\left(\sqrt{w^2- {\it Vo}}-w\right)\,L+\left(\sqrt{w^2-{\it Vo}}+w\right)\,e^{2\,a\,i \,w}\,K\right)}\over{2\,\sqrt{w^2-{\it Vo}}}}$$
$$J={{e^ {- a\,i\,w }\,\left(\left(\sqrt{w^2-{\it Vo}}+w\right)\,e^{a \,i\,\sqrt{w^2-{\it Vo}}}\,L+\left(\sqrt{w^2-{\it Vo}}-w\right)\,e^{ a\,i\,\sqrt{w^2-{\it Vo}}+2\,a\,i\,w}\,K\right)}\over{2\,\sqrt{w^2- {\it Vo}}}}$$
$$\left[ F=J+H-G \right] $$
$$w\,\left(J+H-G\right)+\sqrt{w^2-{\it Vo}}\,J-\sqrt{w^2-{\it Vo}}\,H -w\,G$$
$$w\,\left({{e^ {- a\,i\,w }\,\left(\left(\sqrt{w^2-{\it Vo}}+w \right)\,e^{a\,i\,\sqrt{w^2-{\it Vo}}}\,L+\left(\sqrt{w^2-{\it Vo}}- w\right)\,e^{a\,i\,\sqrt{w^2-{\it Vo}}+2\,a\,i\,w}\,K\right)}\over{2 \,\sqrt{w^2-{\it Vo}}}}+{{e^{-a\,i\,\sqrt{w^2-{\it Vo}}-a\,i\,w}\, \left(\left(\sqrt{w^2-{\it Vo}}-w\right)\,L+\left(\sqrt{w^2-{\it Vo} }+w\right)\,e^{2\,a\,i\,w}\,K\right)}\over{2\,\sqrt{w^2-{\it Vo}}}}- G\right)+{{e^ {- a\,i\,w }\,\left(\left(\sqrt{w^2-{\it Vo}}+w\right) \,e^{a\,i\,\sqrt{w^2-{\it Vo}}}\,L+\left(\sqrt{w^2-{\it Vo}}-w \right)\,e^{a\,i\,\sqrt{w^2-{\it Vo}}+2\,a\,i\,w}\,K\right)}\over{2 }}-{{e^{-a\,i\,\sqrt{w^2-{\it Vo}}-a\,i\,w}\,\left(\left(\sqrt{w^2- {\it Vo}}-w\right)\,L+\left(\sqrt{w^2-{\it Vo}}+w\right)\,e^{2\,a\,i \,w}\,K\right)}\over{2}}-w\,G$$
Answer L(G,K):
$$L={{\left({\it Vo}\,e^{2\,a\,i\,\sqrt{w^2-{\it Vo}}+2\,a\,i\,w}- {\it Vo}\,e^{2\,a\,i\,w}\right)\,K+4\,w\,\sqrt{w^2-{\it Vo}}\,e^{a\, i\,\sqrt{w^2-{\it Vo}}+a\,i\,w}\,G}\over{\left(2\,w\,\sqrt{w^2- {\it Vo}}+2\,w^2-{\it Vo}\right)\,e^{2\,a\,i\,\sqrt{w^2-{\it Vo}}}+2 \,w\,\sqrt{w^2-{\it Vo}}-2\,w^2+{\it Vo}}}$$