This is my first question here. Would anyone be so kind as to explain how I can solve an inequality of the following form?
$$ \lfloor \frac{A}{x} \rfloor = \lfloor \frac{B}{x} \rfloor $$
Here, $ A $, $ B $ and $ x $ are all non-negative integers (i.e., $ \geq 0 $). Further, $ A $ and $ B $ are constants and I am trying to solve for $ x $. For all intents and purposes, you can assume $ A = 4 $ and $ B = 6 $. That is,
$$ \lfloor \frac{4}{x} \rfloor = \lfloor \frac{6}{x} \rfloor $$
Most posts I have read only involve a floor function on one side. Due to limitations in my mathematical abilities, I am unable to generalise solutions from those posts to solve inequalities with floor functions on both sides.
All help is greatly appreciated. Thank you.