I'm stuck with those integrals. Can you give me a hint how to start solving?
$$\int{\frac{\ln(x+1)}{x+1}}dx$$
$$\int{\frac{1}{x^2-1}}dx$$
I'm stuck with those integrals. Can you give me a hint how to start solving?
$$\int{\frac{\ln(x+1)}{x+1}}dx$$
$$\int{\frac{1}{x^2-1}}dx$$
Hint: try the substitution $u=\log(x+1)$
Hint: use partial fractions to write $\dfrac1{x^2-1}=\dfrac A{x-1}+\dfrac B{x+1}$