This is what I have already tried:
$\frac{x^5+2x}{x^2} > y $
$\frac{x^5}{x^2} + \frac{2x}{x^2} > y $
${x^3} + \frac{2}{x} > y $
I am not sure where to go next or if those are the right steps to take. Any help would be appreciated. Thank you.
2026-04-06 05:56:44.1775455004
How to solve the following inequality for x? $\frac{x^5+2x}{x^2} > y $
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