How to solve the limit using the fundamental limit? (without L'Hopital's rule)

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How to solve the following limit:

$\lim_\limits{h\to\frac{\pi}{2}}\dfrac{\cot h}{h-\frac{\pi}{2}}$

Using this fundamental limit:

$\lim_\limits{h\to0}\dfrac{\sin h}{h}=1$

I can't use L'Hopital's rule.

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Use the change of variables $t=h-\frac{\pi}{2}$ to get $$ \lim_{h\rightarrow \frac{\pi}{2}}\frac{\cot(h)}{h-\frac{\pi}{2}}=\lim_{t\rightarrow 0}\frac{-\sin(t)}{t\cos(t)}=-1 $$