I want to find a solution to
$$ \frac{x_1}{x_2 + x_3} +\frac{x_2}{x_1 + x_3} + \frac{x_3}{x_1+x_2} = 4 $$
for $x_1,x_2,x_3>0$, and $x_1+x_2+x_3=1$.
We have $$\frac{x_1}{1-x_1}+\frac{x_2}{1-x_2}+\frac{1-x_1-x_2}{x_1+x_2}=4.$$
Let $\dfrac{x_1}{1-x_1}=s,\dfrac{x_2}{1-x_2}=t,$then $x_1=\dfrac{s}{1+s},x_2=\dfrac{t}{1+t}.$ We then have $$s+t+\dfrac{1-st}{s+t+2st}=4,$$ and $s=x+y,t=x-y,$then$$\frac{4 x^3+3 x^2-4 x y^2+y^2+1}{2 \left(x^2+x-y^2\right)}=4$$ $$y^2=\frac{4 x^3-5 x^2-8 x+1}{4 x-9}$$ which eventually simplifies to solving $$y^2 = x^3 + 121 x^2 + 1144 x + 2704.$$ How can we solve this? I am unfamiliar with eliptic curves, even after reading some basic material, it seems each equation is tackled differently. Is there a routine method for equations like this?
First notice that x=0,y=52 is a solution. Take a tangent to the curve at this point and it will necessarily intersect at another rational point. By successively taking intersections of the curve with either tangents of rational points or the lines passing through two different rational points you can find more rational points.