how to solve this exponential inequality?

Question

I'm studying for the admission test. In particular, this exponential inequality is a little bit tricky. this is the inequality: $$ \left(\frac{2}{e}\right)^x > 1 $$ I've tried to use the change of basis formula to try to solve the logarithm to deduce the result. But it's not the optimal way. Then, I've tried to rewrite 1 as (2/e)^0, and to solve the equation to find the critical point, but it's still not correct. Can you help me?
Thanks in advance.

Answer 1

The question is answered in the comment but it isn't clear.

Since $2/e$ is less than 1 therefore, if we go with $x>0$ in the comments for any $x$, it would yield a wrong result. For example $(2/e)^{50} = 2.17*10^{-7} \leq 1$

However, for $x < 0$ as a first step, should be a good answer, since the equation will be inversed making it $e/2$ which is number over 1 in the first place.

Start from here.

Continuation

I said start from here, when I gave the full answer without supporting it (proof). Therefore, please rewrite everything in an eloquent way.