How to use the Wolfram Language or another tool to find a second order pde solution with initial conditions?

Question

I want to find a solution the Cauchy problem using the Wolfram Language or some other tool.

I have next task: $$ 3\frac{\partial^2 u}{\partial x^2} + 8\frac{\partial^2 u}{\partial x \partial y} - 3\frac{\partial^2 u}{\partial y^2} - 60\frac{\partial u}{\partial x} + 20\frac{\partial u}{\partial y} = 0,\\ u(x,0) = -4e^{2x},~ \frac{\partial u}{\partial y}(x,0) = -9xe^{2x} $$

So, I tried to run this using wolfram notebook:

weqn = 3D[u[x,y],{x,2}] + 8D[u[x,y],{x}, {y}] -3D[u[x,y],{y,2}] - 60D[u[x,y],x] +20D[u[x,y],y] == 0
ic = {u[x,0] ==-4e^(2x), Derivative[0,1][u][x,0] == -9xe^(2x)}
sol = DSolve[{weqn, ic},u,{x,y}]

but I got very big and strange answer (I couldn't even see it in full), may be I did something wrong. The answer of task on a piece of paper is prettier.

And so, can I somehow solve similar tasks using Wolfram or another tool?

Answer 1

I got the answer in the comments under my question. The correct code should be like this:

weqn = 3D[u[x,y],{x,2}] + 8D[u[x,y],{x}, {y}] -3D[u[x,y],{y,2}] - 60D[u[x,y],x] +20D[u[x,y],y] == 0
ic = {u[x,0] ==-4E^(2x), Derivative[0,1][u][x,0] == -9x E^(2x)}
sol = DSolve[{weqn, ic},u,{x,y}]

You should use E instead e, because mathematica.