I have $a_n-a_{n-1}=n$ with some initial conditions $a_0=1, a_2=2, a_3=4, a_4=7$ since there exist $n$, it's inhomogeous equation isn't it?
I know from ODE i can bring the homogenous solution and differentiate it and do a substitution into the original equation to find the particular solution.
But how about this difference equation?
Here is a solution:
$a_n-a_0=a_n-a_{n-1}+a_{n-1}-a_{n-2}+a_{n-2}-a_{n-3}+...+a_1-a_0$
$=n+(n-1)+(n-2)+...+(n-(n-1))$
$=n\times n - \frac {(n-1)n}2=\frac{n^2}2+\frac n2,$
so $a_n=\frac{n^2}2+\frac n2+1$.