How we can find the velocity of the box at time 0?

Question

If we push a box (mass of 2 kilograms) with a force of 4 newton, how we can find the velocity at t= 0 after pushing the box?

i tried: a=f/M; then with integration => v(t) - v(0) = f/m * t; => v(0) = f/m * t +v(t), but we can't here

Answer 1

We know $\text{Force}= \text{Mass}\times\text{Acceleration}$

The formula for acceleration is:

$\text{Acceleration} = \dfrac{\text {Force}}{\text{Mass}}$

So, $\text{Acceleration}= \dfrac 42 N = 2N$

Acceleration gives the rate of change of velocity over time. If the box starts from rest $t = 0$, the velocity at $t = 0$ can be calculated using the equation of motion that relates acceleration, initial velocity, time, and displacement:

$\text{Final velocity} = \text{Initial velocity} + \text{Acceleration}\times\text{Time}$

Assuming that the box starts from rest, i.e. $v = 0$:

$\text{Final velocity}= 0 + 2\cdot 0 = 0 m/s$

So, at $t = 0$, the velocity of the box after applying the force is $0$ m/s if it started from rest.

If it does not start from the rest: Without information about the initial velocity of the box or the duration of the applied force, it’s not possible to calculate the velocity of the box at a time after $t=0.$ If the box starts from rest, then its velocity at $t=0$ would be $0$ m/s. But in this case, as you mentioned, the box does not start from rest. Therefore, more information is needed to provide a precise answer.