$$\displaystyle\int_{1}^{\infty}\dfrac {\{x\}\cos (ax)}{x^b}\mathrm {d}x$$ here $\{x\}$ represents the fractional part and can be denoted by $$\{x\}=x- \lfloor x \rfloor $$
2026-05-16 09:05:29.1778922329
How would you integrate this $\int_{1}^{\infty}\dfrac {\{x\}\cos (ax)}{x^b}\mathrm {d}x$?
109 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in CALCULUS
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