I have the following problem which I'm trying to solve:
We have a highway with four lanes. A research with 1000 drivers is made to check whether the drivers prefer the inner lanes. There are the following results:
Lane 1: 294,
Lane 2: 276,
Lane 3: 238,
Lane 4: 192.
Do the data give enough information to prove that the proportions all the lanes are different?
Test $p_1=p_2=p_3=p_4=0.25$ when $\alpha=0.05$.
My attempt:
My interpretation is that $H_0$ claims that the distribution is Normal distribution with $\mu=2.5$ and that I have to construct a two-tailed test with $Z_{0.025}=\pm1.96$.
My test-statistic is:
$t=\frac{(\bar X-\mu)\sqrt{n}}{s}=\frac{10(2.32800-2.5)}{s}=\frac{-1.72}{s}$, where s is the sample standard deviation.
Is my attempt alright, and if so, how do I find the sample standard deviation so that I test my hypothesis?
Use Chi-Squared Test with the statistic
$\chi^2 = \sum_{1}^{4} \frac{(O_i-E_i)^2}{E_i} = A$
with $O_i$ is observed proportion and $E_i = .25$
Test with compute $\chi^2_{critical}$ P(X^2>=A) in a chi-square distribution with df being 3 and compare it with p = 0.05 and reject the nukl hypothesis that $H_0: p_1=p_2=p_3=p_4$ if $\chi^2_{critical}$ is greater than 0.05.
Thanks