I can't figure out how to solve the polar integral for finding the area!

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I have: $$ \int_{}^{} \int_{}^{}r\,drd\theta.$$

And I have to find the area bounded by $r=2(2-\sin(\theta))^{1/2}$.

I understand how to find the limits of integration for dr, but how would I find it for (dtheta)? I can't use a graphing calculator for this problem and I'm stuck on what I should do to get the integration limits for dtheta. Is there a way to find them without the graph of the figure?

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It's some time ago, but here I go:

I guess you need to find the domain of $\theta$. Which reflects in the question 'What values for $\theta$ are allowed'.

Since the equation doesn't seem to have any problems $\theta \in [0,2\pi]$.

(The equation doesn't have any problems since $2-\sin(\theta)$ is always positive)