Q) How to prove that the sequence:$ 2,4,6,8,...,1000$ is an A.P.$($$Arithmetic$ $Progression$)?
First of all, the $1^{st}$ term of this sequence is $2$ and the common difference of this sequence is also $2$. Therefore this sequence is in A.P.
Doubt:
I can't understand that how we simply tell that the given series is in A.P. with $1^{st}$ term as $2$ and common difference $2$. For e.g. in this given sequence it can might be that $'555'$ is a term of this given sequence. Then how can we say that the sequence $2,4,6,8,...,1000$ is in A.P. if $555$ is a term of this sequence ?
Please clear my doubt.
When you write $2,4,6,8,…$ it is usually meant that there is some obvious pattern to the sequence. And the reader can easily guess, what the sequence is. In this case, it is obvious that the arithmetic progression with the first term $2$ and the difference $2$ is meant. If an author meant another sequence, they should have described their sequence differently.
This is why it is sometimes better to avoid such way of defining a sequence. And just write “arithmetic progression with the first term $2$ and the difference $2$”. So that there is no doubt what exactly is meant.
Your wording of the question (How to prove that this is an arithmetic progression) is a little bit not suitable. The question is rather what is meant by this record.