Below is what I was reading:
If you deposit $£1,000$ in a bank account which is paying $3\%$ compound interest per year. How much interest would be earnt over $3$ years?
The formula used to solve this was:
$$1000 \times 1.03^3 = £1,092.73$$
Then you subtract for the answer:
$$1,092.73 – 1000 = £92.73$$
I then started playing around with the formula, just to get a better understanding.
I did this:
$1,000 \times 0.03^3$ and expected the answer to be $92.73$ but instead I got $0.027$
Why is the answer coming out as $0.027$ and not $92.73$?
According to your expectations, we have that:
$$1000 \times 1.03^3 - 1000 = 1000 \times 0.03^3$$
Which gives us
$$1000 \times (1.03^3-1) = 1000 \times 0.03^3$$
And so
$$1.03^3-1=0.03^3$$
But expanding it out,
$$1.03^3 - 1^3 = 0.03^3$$ $$0.03(1.03^2+1.03+1) = 0.03^3$$ $$1.03^2+1.03+1 = 0.03^2$$
We can see that the RHS is smaller than $1$, but the LHS is bigger than one, so this is not true.