Let $f(x)=\sup(x^3, x^2+1)$, $I=[1,4]$
$\sup(x^3)=64,\ \inf(x^3)=1$
$\sup(x^2+1)=17,\ \inf(x^2+1)=2$
So $\sup(x^3,x^2+1)=\sup(64,17) =64$
Is this correct, can I have good example.
Let $f(x)=\sup(x^3, x^2+1)$, $I=[1,4]$
$\sup(x^3)=64,\ \inf(x^3)=1$
$\sup(x^2+1)=17,\ \inf(x^2+1)=2$
So $\sup(x^3,x^2+1)=\sup(64,17) =64$
Is this correct, can I have good example.
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No, you misunderstood the definition of the function $f$: it is the function which, for each $x\in[14]$, takes the value $\sup(x^3,x^2+1)$. For instance
&c.