I need to solve this limit without using L'Hospital's rule.
$$\lim_{x\to 0}(\cos x)^\left(\frac{-4}{x^2}\right)$$
Hint:
$$(\cos x)^{-4/x^2}=(1-\sin^2x)^{-2/x^2}=\left(\left(1-{1\over\csc^2x} \right)^{\csc^2x}\right)^{-2\left(\sin x\over x\right)^2}$$
Can you (and/or your friend) take it from there?
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Hint:
$$(\cos x)^{-4/x^2}=(1-\sin^2x)^{-2/x^2}=\left(\left(1-{1\over\csc^2x} \right)^{\csc^2x}\right)^{-2\left(\sin x\over x\right)^2}$$
Can you (and/or your friend) take it from there?