If a 10-digit number 2094x843y2 is divisible by 88, then the value of (5x— 7y) for the largest possible value of x, is:

Question

options

3,5,2,6

my take

3y2 is divisible by 8 if y = 1 or 5 or 9

If y = 1, then

2094x84312 is divisible by 11 if x = 1

If y = 5, then

2094x84352 is divisible by 11 if x = 8

 5x – 7y

If y = 9, then

2094x84392 is divisible by 11 if x = 4    

For the largest possible value of x if x = 8 and y = 9

(5x – 7y) = 5 × 8 – 7 × 9 = 40 – 63 = -23

where am i wrong here ?