If $A$ and $B$ are proper ideals of a ring with no zero divisors, show that $A\cap B \neq \{0\}$

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If $A$ and $B$ are proper ideals of a ring with no zero divisors, show that $A\cap B \neq \{0\}$

Ideals: A subset $I$ of a ring $R$ is called an ideal if

  1. $I$ is a subring of $R$

  2. For all $a\in I,r\in R$ $ar\in I$ and $ra\in I$.

$A$ and $B$ both satisfy the above. How to show that $A\cap B \neq 0$?

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Hint:

If $a\in A$ and $b\in B$, where is $ab$?