$a +b $ = 5 and $ab = 6$ . Find $\cfrac{1}{a}$ + $\cfrac{1}{b}$
Any Ideas on how to begin?
Many Thanks
$$\frac { 1 }{ a } +\frac { 1 }{ b } =\frac { a+b }{ ab } =\frac { 5 }{ 6 } $$
Since $a+b = 5$ and $ab = 6$, then $a,b$ can be the roots of polynomial $x^2-5x+6=0$
By fraction, $(x-2)(x-3) = 0$.
Out of symmetry, let $a = 2,b=3$, so $\frac{1}{a}+\frac{1}{b}= \frac{5}{6}$
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$$\frac { 1 }{ a } +\frac { 1 }{ b } =\frac { a+b }{ ab } =\frac { 5 }{ 6 } $$