If $[A,B]$ and $A$ are in Lie algebra $\mathcal{L}$ then does this imply that $B \in \mathcal{L}$?
2026-04-20 02:50:17.1776653417
If $[A,B], A \in \mathcal{L}$ then does this imply that $B \in \mathcal{L}$?
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1
An ideal $I$ of a Lie algebra $\mathfrak{g}$ is a subspace of $\mathfrak{g}$ such that \begin{equation} [\mathfrak{g},I] \subseteq I. \end{equation} The ideal $I$ forms a subalgebra of $\mathfrak{g}$.
Therefore if the Lie algebra $\mathcal{L}$ in the question is some ideal and one chooses any $A \in \mathcal{L}$ and some $B$ in the larger algebra then we would get \begin{equation} [A,B] \in \mathcal{L}. \end{equation} even for $B \notin \mathcal{L}$.
This provides a counter example and so the answer to the question is a (somewhat resounding) NO!