If A:B is 2:3, B:C is 4:5 and C:D is 6:8. Find A:B:C:D?
I am able to find A:C , B:D.
$\frac{A}{C} = \frac{A}{B} × \frac{B}{C}$
$\frac{B}{D} = \frac{B}{C} × \frac{C}{D}$
But I am not able to find A:B:C:D.
If A:B is 2:3, B:C is 4:5 and C:D is 6:8. Find A:B:C:D?
I am able to find A:C , B:D.
$\frac{A}{C} = \frac{A}{B} × \frac{B}{C}$
$\frac{B}{D} = \frac{B}{C} × \frac{C}{D}$
But I am not able to find A:B:C:D.
Given,
$A:B = 2:3$
$A=2x, B=3x$
$B:C = 4:5$
$B=4x, C=5x$
Now in above two ratios in first B has 3x value and in second B has 4x value. Take LCM of 3x, 4x. You have 12x.
To make the value of B in first ratio to 12x . Multiply first ratio with 4x and in other ratio with 3x.
You have,
$A:B = 8x:12x$ and $B:C = 12x:15x$
On combining these two,
$A:B:C = 8x:12x:15x$
Now,
$C:D = 6:8$
$C = 6x, D = 8x$
Now in above two ratios in first C has 15x value and in second C has 6x value. Take LCM of 15x, 6x. You have 30x.
To make the value of C in first ratio to 30x . Multiply first ratio with 2x and in other ratio with 5x.
$A:B:C = 16x:24x:30x$
$C:D = 30x:40x$
On combining these two,
$A:B:C:D = 16x:24x:30x:40x$
If eliminate x.
We have $A:B:C:D = 16:24:30:40$
You can also divide ratio by 2 because all terms have 2 in common.