The number $\frac{22}{7}$ is irrational in our base-$10$ system, but in, say, base-$14$, it is rational (it comes out to $3.2$ in that system).
It's easy for fractions that are irrational as decimals, as you can just represent them in a base that's double the denominator of the fraction. However, what if I have a number like $\pi$, or $\log(2)$?
For those numbers, it could easily be represented as a rational number if it is in base-($\pi\cdot 2$) or base-($\log(2)\cdot 2$), but is it possible to represent them in any rational-based number system?
Always refer to definitions, a number $x$ is called irrational iff $\forall p,q \in \Bbb Z : x\neq\frac pq$, that is when you can't express it as ratio of two integers, not based on how it looks using a different number system. EDIT: This means that you can never find two integers to precisely equal $\pi$ for example, $\frac 31$, $\frac{22}{7}$, $\frac{333}{106}$, $\frac{355}{113}$, $\frac{103993}{33102}$ $\dots$ won't equal $\pi$, they're all finite decimals, the real irrational $\pi$, has unending decimals.