If Arg$(z)=3\pi/4$ and Arg$(w)=\pi/2$, then why is Arg$(zw)=-3\pi/4$ instead of the sum, $5\pi/4$?

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A question from my textbook asks, given $\operatorname{Arg}(z) = 3\pi/4$ and $\operatorname{Arg}(w) = \pi/2$, to find $\operatorname{Arg}(zw)$. So, I add $\operatorname{Arg}(z)$ and $\operatorname{Arg}(w)$ and get $5\pi/4$.

But when I check the solution they mention it in the following form: $5\pi/4 - 2\pi = -3\pi/4$.

Why is it mentioned in this form?

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If $\theta$ is an argument for $z$, then so are the numbers $\theta + 2\pi k$ for all integers $k$ (since $re^{i\theta}=re^{i\theta +2ki\pi}$).

But $\operatorname{Arg}(z)$, with capital "A", is usually defined to be the specific argument that lies in $(-\pi,\pi]$. That is, you always must have $-\pi< \operatorname{Arg}(z)\leq \pi$. (There are other definitions of the "principle" range, but this is pretty common.)

So you need to add or subtract integral multiples of $2\pi$ to your answer until the result is in the required range.