Show that if $f,g: [a,b] \rightarrow \mathbb{R}$ are Riemann integrable then $\sqrt{f^2+g^2}$ is Riemann integrable and
$\int_a^b \sqrt{f^2 + g^2} dx \leq \int_a^b |f| dx + \int_a^b |g| dx$
So I'll start by writing down what I know:
I know by arithmetic of integrals that $|\int_a^b fg dx| \leq \sqrt{\int_a^b f^2} dx \cdot \sqrt{\int_a^b g^2 dx}$.
I also know that the function will be RI iff: $\exists P=\{a=x_0, x_1, ... , x_n = b\} \text{ a partition}$ s.t $U(f,p) - L(f,p) < \epsilon$. Finally, if f is any bounded function then $\overline{\int} f dx \geq \underline{\int} f dx$.
And so to prove Riemann integrability I'm guessing we let choose partitions such that:
$U(f,p_1) - (\text{ some } \epsilon ) < \int_a^b fdx < L(f,p_1) + (\text{ some } \epsilon)$. Similarly for $p_2$.
Let $P = P_1 \cup P_2$ band let $x,y \in [X_{i-1}, x_i]$ for some $1 \leq i \leq N$. And so we're left with
$\sqrt{(f^2(x) + g^2(x)) - ((f^2(y)-g^2(y))}$
I know I'm supposed to show that the above is less than something, and do an $\epsilon$ argument, but I really can't figure it out.
As for proving the inequality,
$\sqrt{U(f^2+g^2,p)} \leq \sqrt{\sum \sup f^2+g^2 \Delta x_i}$ And again, I don't know how to proceed.
Help would be much appreciated!
$f,g$ are Riemann-Integrable $\implies f^2,g^2$ are Riemann-Integrable
$f,g$ are Riemann-Integrable $\implies f+g $ are Riemann-Integrable
$ h$ is Riemann-Integrable $\text {and} h\ge 0 \implies \sqrt h$ is Riemann-Integrable
Now combine all three.