Today I argued with my math teacher about this:
$\gcd(8n^2 + 6n; 8n^2 + 10n) = 20$ and we have find $\text {lcm}(n^2 + n; n^2 + 3n)$
2026-03-28 06:00:34.1774677634
If $\gcd(8n^2 + 6n; 8n^2 + 10n) = 20$, find $\text {lcm}(n^2 + n; n^2 + 3n)$
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If I have understood the problem correctly, given $$20=\gcd(8n^2 + 6n; 8n^2 + 10n) =2n\gcd(4n + 3; 4n + 5)=2n\gcd(4n + 3; 2)$$ we have to find $$\text {lcm}(n^2 + n; n^2 + 3n)=n\text {lcm}(n+1; n+3).$$ The first line tells us something about $n$...
P.S. I read from your profile that you are a 8th grade student. So please ask if you need further help.