Let
- $d\in\mathbb N$
- $\Omega\subseteq\mathbb R^d$ be non-empty and open
- $\phi:\Omega\to\mathbb R$ be continuous with compact support $\operatorname{supp}\phi$
Can we find a closed ball $K$ such that $K\subseteq\Omega$ and $K':=\operatorname{supp}\phi\subset K$?
Take $\Omega = B(0,2) \backslash \bar{B}(0,1)$, and $\phi(x) = \|x\| - 3/2$.
Then $K' = \{ x \in \Omega | \|x\| = 3/2 \}$, and there is no ball that contain $K'$ that is inclued in $\Omega$