If $\phi:R\to S$ is an injective ring homomorphism, then is $\phi(R)\cong R$?
I cannot find anything like this anywhere, and it looks like it can be true. Just define $\psi:R\to \phi(R)$ by $\psi(r)=\phi(r)$. However, I could be wrong...
2026-03-25 14:34:42.1774449282
If $\phi:R\to S$ is an injective ring homomorphism, then is $\phi(R)\cong R$?
60 Views Asked by user482939 https://math.techqa.club/user/user482939/detail AtRelated Questions in ABSTRACT-ALGEBRA
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