Let $\zeta(s)$ be the Riemann zeta function.
Assume RH is false , is it possible that we have in the critical strip $\zeta(a_1+ti) = \zeta(a_2+ti) = \zeta(a_3+ti) = \cdots = \zeta(a_n+ti) = 0$
For $a_n$ real and $t$ real and $n$ an integer > 2 ?
Can we put restrictions on the divisors of $n$ ?
In particular I wonder if $n=3$ is possible. I wonder because then we have by symmetry of the zero's also a real part $1/2$ ; $1/2+ti$ must then be a zero.
Does the multiplicity of the $\zeta$ zeroes have any effect on this ?