If ${\rm Aut}(G)$ is locally cyclic then $G$ is abelian

78 Views Asked by At

It is a very common exercise in elementary group theory to prove that if ${\rm Aut}(G)$ is cyclic then $G$ is abelian. The usual proof seems to not require it to be cyclic but just locally cyclic. Is this correct? Are there any interesting further generalizations?